(2x)^2/0.1-x

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Solution for (2x)^2/0.1-x equation: 


x in (-oo:+oo)

((2*x)^2)/0.1-x = 0

40*x^2-x = 0

DELTA = (-1)^2-(0*4*40)

DELTA = 1

DELTA > 0

x = (1^(1/2)+1)/(2*40) or x = (1-1^(1/2))/(2*40)

x = 1/40 or x = 0

x in { 0, 1/40 }

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